STA301 Quiz No.2 Shared by M_Malik

Question # 1 of 10 (Start time: 06:44:02 PM)Total Marks: 1
In the method of moments, how many equations are required for finding two unknown population parameters?
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1

2

3

4

Question # 2 of 10 (Start time: 06:45:31 PM)Total Marks: 1
For statistical inference about the mean of a single population when the population standard deviation is unknown, the degrees for freedom for the t distribution equal n-1 because we lose one degree of freedom by using the:
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Sample mean as an estimate of the population mean
Sample size as an estimate of the population size
Sample proportion as an estimate of the population proportion
Sample standard deviation as an estimate of the population standard deviation

Question # 3 of 10 ( Start time: 06:47:31 PM )          Total Marks: 1
An urn contains 4 red balls and 6 green balls. A sample of 4 balls is selected from the urn without replacement. It is the example of:
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Binomial distribution
Hypergeometric distribution
Poisson distribution
Exponential distribution

Question # 4 of 10 ( Start time: 06:48:17 PM )          Total Marks: 1
An estimator is always a:
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Statistic
Random variable
Statistic and Random variable
Parameter

Question # 5 of 10 ( Start time: 06:49:50 PM )          Total Marks: 1
The Chi- Square distribution is continuous distribution ranging from:
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Zero to infinity
Minus infinity to plus infinity
Minus infinity to one
One to plus infinity

Question # 6 of 10 ( Start time: 06:51:10 PM )          Total Marks: 1
In a Geometric distribution, Maximum Likelihood Estimator (MLE) for proportion (P) is equal to:
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Sample mean
Reciprocal of the mean
Sample variance
Reciprocal of the sample variance

Question # 7 of 10 ( Start time: 06:52:45 PM )          Total Marks: 1
Let X be a random variable with binomial distribution, that is (x=0,1,…, n). The Var[X] is:
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P 
NP
NP (1-p)
Xnp

Question # 8 of 10 ( Start time: 06:54:23 PM )          Total Marks: 1
ANOVA stands for
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Analysis of variance
Analysis of covariance
Analysis of variables
All above

Question # 9 of 10 ( Start time: 06:55:37 PM )          Total Marks: 1
If an estimator is more efficient then the other estimator, its shape of the sampling distribution will be
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Flattered
Normal
Highly peaked
Skewed to right

Question # 10 of 10 ( Start time: 06:56:34 PM )        Total Marks: 1
How can we interpret the 90% confidence interval for the mean of the normal population?
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There are 10% chances of falling true value of the parameter
There are 90% chances of falling true value of the parameter
There are 100% chances of falling true value of the parameter
All are correct